10x^2+40x+30x=180

Solution for 10x^2+40x+30x=180 equation:

10x^2+40x+30x=180

We move all terms to the left:

10x^2+40x+30x-(180)=0

We add all the numbers together, and all the variables

10x^2+70x-180=0

a = 10; b = 70; c = -180;
Δ = b2-4ac
Δ = 702-4·10·(-180)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-110}{2*10}=\frac{-180}{20}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+110}{2*10}=\frac{40}{20}
=2
$